Show your work. In humans, right handed is dominant to left. Widow's-peak hairline is dominant over non-widow's-peak hairline. Which one is the possible dihybrid genotype of their child? Thank you=), Where do wild hamsters like to sleep? If a woman with freckles has a son that does not. A. A blue-eyed parent and a heterozygous brown-eyed parent would like to have children together. What is the man'. A) 0 B) 1 C) 2 D) 3 E) 4, The allele for albinism (a) is recessive to the allele for normal pigmentation (A). b. A blue-eyed parent and a heterozygous brown-eyed parent would like to have children together. What is the probability that an offspring will have a homozygous dominant genotype? a) 50%! Assume both parents are heterozygous for six fingers. In humans, the allele for short fingers is dominant over that for long fingers. A woman with freckles has a son that does not. Which one is the possible dihybrid genotype of their child? A woman who cannot roll her tongue, and is heterozygous for having freckles, mates with a man who is homozygous dominant for both traits. What is the mother's phenotype? A blue-eyed parent and a heterozygous brown-eyed parent would like to have children together. Having freckles (F) is dominant over not having freckles ( and having a widow's peak (W) is dominant over not having a widow's peak (wl. Two persons with freckles and dimpled cheeks have two children: In humans, the presence of freckles is determined by one gene. Write the letter for the dominant allele. How could this happen? The allele for having freckles (F) is dominant over the allele for not Become a Study.com member to unlock this answer! What is the probability that exactly two of their first three children will have brown eyes? Considering that Noor and Hamza do produce a first childand name her Roop, what is the likelihood Roop will be acarrierof PKU, like her mother was? A blue-eyed parent and a heterozygous brown-eyed parent would like to have children together. There is a 100% chance that their child will have green hair. Start your trial now! Her mother has blonde hair and her father has brown hair. Both parents have purple hair. B. out in the open g = purple hair. What would have been the genotype of the mother? Assume freckles and dimples are dominant traits. Sally does not have freckles because she has a heterozygous for freckles . Also, unattached earlobes are dominant to attached earlobes. In humans, six fingers (F) is the dominant trait, five fingers (f) is the recessive trait. A woman with freckles has a son that does not. All rights reserved. All the F1 plants had green pods. The attached earlobes allele (E) is dominant to the unattached earlobes allele (e). In humans, the allele for dimples (D) is dominant. Determine the ge, The allele for brown eyes (B) is dominant, while the allele for blue eyes (b) is recessive. Melanocytes are skin cells which produce pigment. Explain. What is the chance that their child will have freckles? What would have to be the genotype of the mother? In humans, the allele for having dimples is dominant to the allele for not having dimples is recessive. b) 0%! What is the phenotype of a homozygous dominant? b. Assume genes for freckles is recessive, a woman without freckles has a son that has freckles. b. Her father does, too, but her mother does not. A grey cat homozygous for curled ears is. l! In humans, having freckles (F) is dominant over not having freckles (. Use a Punnett Square and give the phenotype and genotype for their offspring. A blue-eyed parent and a heterozygous brown-eyed parent would like to have children together. One parent is heterozygous for cleft chin, and the other parent does not have a cleft chin? The allele for not having dimples (d) is recessive. Having freckles is dominant over not having freckles. Freckles are caused by a dominant allele. (a) (b) (c) 116 (d) 132 (e) 164, Individuals of genotype AaBb were crossed with aabb individuals. A man who has no freckles and flat feet marries a woman who is homozygous dominant for both traits. A woman with freckles has a son that does not. A. d. multiple alleles. In humans , the allele for brown eyes (B) is dominant. A woman with unattached. A man who has no freckles and flat feet marries a woman who is homozygous dominant for both traits. Tom does not have freckles, but his mother and father do. In humans, having freckles (F) is dominant over not having freckles (f). This is because freckles is a dominant trait and even one allele of dominant treat is enough to cause freckles to the offspring. Select one: a. Homozygous dominant. A) 0 B) 1 C) 2 D) 3 E) 4, In humans, W=widows peak while w=normal hair line and A=attached earlobes while a= unattached earlobes. (b) What is the predicted frequency of homozygous dominant? What are the genotype of the parents? In humans, having freckles (F) is dominant over not having freckles (f). 78 LAB 3 Inheritance Name SCENARIO B For this exerciso, work alone or in a small group to complete the dihybrid cross and answer the questions that follow Consider two traits in humans: freckles and widow's peak (w Having reckles is dominant over not having freckles (), and having a widow's peak (W) is dominant over not having a widow's peak (w). A man and woman seek genetic counseling. Both a man and woman are heterozygous for freckles. If a woman (DD) and a man (Dd) have four children, how many of the children will not have dimples? What is the probability that their first child will, In humans, pigmented skin is dominant over albino (non-pigmented) skin, and a dimple in the chin is a dominant characteristic. Inheritance is, A: There are some traits that are regulated by only one gene such traits are explained very well by, A: The genetic composition of a particular organism Genotype refers to the genetic composition of that, A: According to Hardy-Weinberg principle, genotype frequencies and alleles in a population remain the, A: The variation of a gene that occurs at the same locus of a chromosome is called an allele. They have a child that has no widow's peak and no freckles. Since . What are the chances of this. A freckled tongue-roller could have which of the following genotypes? If they have eight children, how many will have freckles? All other trademarks and copyrights are the property of their respective owners. . What is the probability that none of their first three children, In humans, the allele for dimples (D) is dominant. A father has the genotype WW, and the mother has the genotype Ww. Solved So far, you have worked on Punnett squares that show - Chegg A woman who cannot roll her tongue, and is heterozygous for having freckles mates with a man who is homozygous dominant for both traits. b. In a large lecture class, the earlobes of 112 students we. C. If two individuals who are heterozygous for both traits are crossed, what is the ratio of traits in their offspring? The allele for dark hair dominates the allele for light hair. The allele for not having dimples (d) is recessive. Select one: a. a.) Explain. If a woman with genotype BB and a man with genotype Bb have 4 children, how many of the children will have blue eyes? Assign the appropriate alleles to the individuals and write the possible cross. It is encoded by the genes present on the, A: Homozygous dominant is trait in which both the identical alleles are dominant . Having freckles (F) is dominant over not having freckles (f). b. What percentage of their children will have freckles? b. codominance. The aliens can also be tall or short. XHXH/ XHXh= Normal female c.) Fill in the Punnett. Show the genotype and phenotype ratios expected among their children. Unattached earlobes are a dominant trait. Assume the gene for freckles is dominant (F). If two individuals heterozygous for freckles have a child, what is the probability the child will have freckles? What is the genotype of the father? When a woman (DD) and a man (Dd) have four children, how many of the children will not have dimples? Createyouraccount. The allele for blue eyes (b) is recessive. A normally pigmented woman whose father is an albino marries an albino man whose parents are normal. Explain how this would happen. If an individual is homozygous dominant for both traits and is crossed with a homozygous recessive individual for both traits, w. Freckles is an autosomal dominant trait. A woman who cannot roll her tongue, and is heterozygous for having freckles mates with a man who is homozygous dominant for both traits. What is the probability that none of their first three children, In humans, the brown eye allele is dominant to the blue eye allele of one of the eye color genes. What is the probability that the. In humans, pigmented skin is dominant over albino (non-pigmented) skin, and a dimple in the chin is a dominant characteristic. If an individual is heterozygous for both traits and crossed with an individual who is homozygous recessive for both traits, what is the ratio of traits in their offspring? Such traits are termed as sex, A: Autosomal recessive disorder manifests when an individual possesses two mutated or abnormal alleles, A: It states that a diploid organism passes a randomly selected allele for a trait to its offspring,, A: In humans, sex is determined by the presence of Y chromosome. What is the father's phenotype? Dimpled cheeks (D) is dominant to non-dimpled . A man heterozygous for both traits marries a woman heterozygous for both traits. The man has fathered a child with a woman that does not have freckles. Demonstrate a sex-linked traits punnet square and explain what the expected o, Genetic studies of an animal show that eye colour is controlled by an autosomal gene with the dominant allele (R) for red colour and the recessive allele (r) for yellow eye colour. The presence of freckles (F) is dominant to the absence of freckles (f). If there are 201 people with freckles in a population of 300 people: (a) What is the predicted frequency of heterozygotes? 0 b. B. What can be the possible offspring from a cross between two heterozygous freckled broad nose people? 0__ See answers Advertisement s15159851 Answer: The answer is 100% Explanation: Use the punnett square thereom to solve. What is the phenotype of a homozygous recessive? If a woman (DD) and a man (Dd) have four children, how many of the children will not have dimples? What is the woman's genotype? 2. . 9: freckles/ 6 fingers 3: freckles/ no 6 finge. What is the probability that the, The ability to roll your tongue and having freckles are both autosomal dominant traits. Show the expected children of a blue-eyed man with a brown eyed woman whose mother had blue eyes. Heterozygous means a, A: Given: Two alleles for brown eyes The allele for not having dimples (d) is recessive. Hairy knuckles are dominant to non-hairy knuckles is humans. Having freckles is dominant over not having freckles. A person who is heterozygous for, The ability to roll your tongue and having freckles are both autosomal dominant traits. It is the allele that is, A: Genetics is the branch of biology that studies genes, including their structure, function, genetic, A: In dominance, one allele is completely dominant over another. A woman who cannot roll her tongue, and is heterozygous for having freckles mates with a man who is homozygous dominant for both traits. 1 C. 2 D. 3 E. 4, In humans, the allele for dimples (D) is dominant. Some characteristics in people are inherited as simple dominant and recessive traits. Dominant B. Recombinants C. Parental D. Recessive E. Hybrids. Freckles is a dominant trait. Black spots are dominant to brown spots Homozygous black Brown spots b. What is his genotype? In a family, both parents have freckles and a widow's peak. C. in the underground borrow 0 \\ B. A blue-eyed parent and a heterozygous brown-eyed parent would like to have children together. Select one: a. Homozygous dominant. Get access to this video and our entire Q&A library, What is Heterozygous? Pattern of inheritance is governed by both the parents. ff _______________ Ee _______________ FF _______________ EE _______________ Ff _______________ ee _______________. E. Carriers. Parent gen.: heterozygous for freckles a. A man who has no freckles and flat feet marries a woman who is homozygous dominant for both traits. If a woman (DD)and a man (Dd) have four children, how many of the children will not have dimples? Question 1 1 out of 1 points In humans, having freckles (F) is dominant over not having freckles (f). A pedigree. What are the chances of thi. A man heterozygous for both traits marries a woman heterozygous for both traits. 0 B. A brown-eyed woman who has a blue-eyed child would have the genotype: A. Bb. This method was devised and named after the geneticist, Reginald Punnett. If an individual is homozygous dominant for both traits and is crossed with a homozygous recessive individual for both traits, what is the ratio of traits in their offspring? a. RRFF b. RrFf c. rrFF d. RRFF and RrFf on. Attached earlobes are recessive to free earlobes. For each genotype, indicate the phenotype: The freckles allele (F) is dominant to the no freckles allele ( f). In this lesson, learn the heterozygous genotype definition, see if heterozygous is dominant, recessive, or both, and learn what a heterozygous mutation is. In cats, curled ears results from an allele (Cu) that is dominant over an allele (cu) for normal ears. What are the possible genotypes of someone with freckles? a) 3 b) 0 c) 2 d) 4 e) 1, Whether an allele is dominant or recessive depends on: a. 2/3. B) heterozygous dominant for bo, In humans, the allele for dimples (D) is dominant. D. Ff dd times. The allele for not having dimples (d) is recessive. How many of the children will not have dimples? If a woman with freckles has a son that does not, what would have to be the genotype of the mother? The Punnett square shows the possible genotypes of the offspring. 1 point F 2 4 Refer to the illustration above. Assume the gene for freckles is dominant. copyright 2003-2023 Homework.Study.com. See answer Advertisement grayson1717 6 of them will have freckles because with four three would have freckles so multiply by two Advertisement What is the man'. In humans, having freckles is dominant over not having freckles What genotype(s) will her gametes have? In crossing a homozygous recessive individual with a heterozygote, what is the chance of getting an offspring with the homozygous recessive phenotype? What is the man's phenotype? Dimples (D) are dominant over no dimples (d). In humans, having freckles is dominant to not having freckles. Freckles are caused by a dominant allele. B. Leslie, who does not have freckles, and Erin, who has freckles, are parents to 3 kids, who all have freckles. A father has the genotype WW, and the mother has the genotype Ww. If a woman with genotype BB and a man with a genotype Bb have four children. His maternal grandfather has freckles. a. PUNNETT SQUARE REVIEW | Science Quiz - Quizizz Freckles (F) are dominant over no freckles (f). a) What are their possible genotypes? A woman who cannot roll her tongue, and is heterozygous for having freckles mates with a man who is homozygous dominant for both traits. Given that the offspring of human parents have the dominant phenotype freckles and cleft chin, the parent's gametes could be: A) homozygous dominant for both genes in father: heterozygous dominant for both genes in mother. A) 0 B) 1 C) 2 D) 3 E) 4, In humans, the brown eye allele is dominant to the blue eye allele. 2/3. Since Tom does not have any freckles, and having freckles (F) is dominant over not having freckles (f), his genotype must be homozygous recessive, ff. Our experts can answer your tough homework and study questions. To learn further about monohybrid cross click the given link below: A: Freckles (Ff) B:No freckles (ff) C: Freckles (Ff) D:No freckles (ff), This site is using cookies under cookie policy . They have a child that has no widow's peak and no freckles. Freckles are dominant over no freckles. Two parents both have freckles. Two individuals with freckles and dimples have a child with no freckles and no dimples. 1. FF Explain your answer. If one parent is blue-e, In humans, six fingers (F) is the dominant trait, five fingers (f) is the recessive trait. If the mother is the carrier (X^BX^b)and the father is normal (XBY) (Note: B is the dominant allele; b is the rece, Consider a cross between an individual heterozygous for hitchhiker's thumb and homozygous recessive for freckles (Jjrr, normal thumb and no freckles) and an individual homozygous dominant for both traits (JJRR, Normal thumb and freckles). How many of the children will not have dimples? How many of their children are likely not to have freckles? Unattached earlobes are a dominant trait. a) What is the father's phenotype? What is. If A denotes the allele for unattached earlobes, and a denotes the allele for attached earlobes, what is (are) the possible genotype(s) of a person who has unattached earlobes? Use the following symbols: F = gene for free earlobes, f = gene for attached earlobes. True or False. A woman who cannot roll her tongue, and is heterozygous for having freckles mates with a man who is homozygous dominant for both traits. Show. What is the phenotype of the mother? Two individuals with freckles and dimples have a child with no freckles and no dimples.
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